5b^2-26b=26

Solution for 5b^2-26b=26 equation:

5b^2-26b=26

We move all terms to the left:

5b^2-26b-(26)=0

a = 5; b = -26; c = -26;
Δ = b2-4ac
Δ = -262-4·5·(-26)
Δ = 1196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1196}=\sqrt{4*299}=\sqrt{4}*\sqrt{299}=2\sqrt{299}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{299}}{2*5}=\frac{26-2\sqrt{299}}{10}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{299}}{2*5}=\frac{26+2\sqrt{299}}{10}
$